Algebra Midterm #2 Review
Algebra Midterm #2 Review
Chapter 9: Inequalities
- §9.1: Inequalities and Domain
- Meaning of <, >, ≤, ≥
- Solving inequalities algebraically or graphically
- Remember: multiplying or dividing by a negative reverses the inequality!
- Writing solution as a number line graph, in interval notation, in set-builder notation
- Finding domain of square root functions (set radicand ≥ 0 and solve)
- §9.2: Intersections, Unions, and Compound Inequalities
- Set theory operations:
- Intersection: A∩B = {all things that are in A and in B}
- Union: A∪B = {all things that are in A or in B}
- Note that A and B can be intervals
- Compound Inequalities: two or more inequalities combined with "and" or "or"
- Mathematically, "and" means that all of the statements must be true
- Mathematically, "or" means that at least one of the statements must be true
- Be careful which one to use in the solution!
- §9.3: Absolute Value Equations and Inequalities
- Geometrically, |A| means "distance from A to 0"
- Algebraically, |A| means "A" if A ≥ 0, or "−A" if A < 0
- This means that if |A| = B, then A might be B or A might be −B.
- So write "A = B or A = −B" and solve both equations.
- Note that if B is negative, there is no solution!
- You may need to isolate the absolute value first.
- To solve an inequality with absolute value, first treat it as an equation.
- Solving this equation will tell you the boundary points.
- Mark boundary points on a number line and test a sample point in each interval.
- This will determine where the original inequality is true and where it's false.
- Write solution set in interval notation or as a compound inequality.
- §9.4: Inequalities in Two Variables (typically x & y)
- Again, treat it as an equation to graph the boundary line
- Use a solid line for ≤ (boundary included) or dashed for < (boundary excluded)
- And again, test a sample point not on the line (origin is usually easiest)
- If that point makes the inqeuality true, shade that side; otherwise, try another point
- Systems of inequalities: shade only the region that makes ALL of the inequalities true
- Try graphing one at a time, and use small arrows to denote "shaded" side
- This is useful for describing a region of the plane
- Each inequality can be thought of as "slicing" what's left of the plane
Chapter 10: Radicals
- §10.1: Radical Expressions & Functions
- Terminology: radical, radicand, index, principal square root
- Difference between odd and even roots when dealing with negatives
- §10.2: Rational Numbers as Exponents
- Review the Laws of Exponents! (page 645)
- Fractions as exponents: A1/n = n√(A); more generally Am/n = n√(Am) = n√(A)m
- A negative exponent means taking the reciprocal of the base; A−n = 1/An
- Sometimes converting all radicals to exponents can be helpful for simplifying.
- §10.3: Multiplying Radical Expressions
- Since radicals are exponents, they distribute over multiplication: n√(A·B) = n√(A) · n√(B).
- To simplify, factor out any perfect nth powers and split the radical.
- §10.4: Dividing Radical Expressions
- Similarly, radicals distribute over division: n√(A/B) = n√(A) / n√(B)
- Sometimes combining into one radical first, reducing, and THEN simplifying works well.
- Don't leave any fractions in radicals, and don't leave any radicals in the denominator!
- Rationalizing the denominator:
- multiply top and bottom by whatever is needed to cancel the denominator's radical
- §10.5: Expressions Containing Several Radical Terms
- In sums, identical radicals can be factored out, or combined as like terms (same thing)
- Sometimes "like terms" may appear after all radicals are fully simplified
- §10.6: Solving Radical Equations
- Isolate the radical and raise both sides to a power to cancel out the root.
- If there are two radicals, isolate one and raise to a power. Repeat for the other.
- Once the radicals are gone, solve what's left (typically linear or quadratic).
- Always check for extraneous solutions, especially when dealing with even roots!
- §10.7: Geometrical Applications
- Pythagorean Theorem: (leg1)2 + (leg2)2 = (hypotenuse)2
- Substitute in the measurements you know and solve for the one you don't.
- "Special Triangles": 45°-45°-90° (isosceles) and 30°-60°-90° (half of an equilateral)
- You can always re-work these from scratch if you forget the proportions.
- Distance Formula: distance = √( (Δx)2 + (Δy)2 ) ... really the Pythagorean Theorem!
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